A solution containing 1.20 g of impure sodium hydroxide solution per Liter. In a titration, it requires 18.5 L of 0.500 mol/ L of sulfuric acid to neutralize 20.0 L of the impure alkaline solution completely. The chemical reaction is shown below. 2NaOH + H2SO4 Na2SO4 + 2H2O

Determine the concentration of NaOH in mol/L

the answer is the first option

explanation:

just googled it m8. not that hard

lol

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).

answeridentity;