Black hair (B) is dominant to brown hair (b). Cross a black rabbit and a brown hair. The black rabbit had a brown haired mother. What is the punnet square for this and the genotype and phenotype for this.​

Genotypic ratio = 1 Bb: 1 bb

Phenotypic ratio = 1 black rabbit : 1 brown rabbit

Explanation:

This question involves a gene coding for hair color in rabbits. The allele for Black hair (B) is dominant to the allele for brown hair (b).

According to this question, a black rabbit whose mother is brown haired (bb) is crossed with a brown hair rabbit. This means that the black rabbit will have a genotype 'Bb' while the brown rabbit will have a genotype 'bb'. Each parent will produce the following gametes:

Bb - B and b

bb - b and b

Using these gametes in a punnet square (see attached image), the following proportion of offsprings will be produced:

Bb, Bb, bb and bb

This means that the;

Genotypic ratio = 1 Bb: 1 bb

Phenotypic ratio = 1 black rabbit : 1 brown rabbit

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%