Acid spills are often neutralized with sodium carbonate. For example Na CO2 (s) + H2SO4 (aq) → Na2SO4 (aq) + CO2(g) + H20 (1)
An instructor dropped a 2.50 L bottle of 18.0 M H2SO4 on a cement floor.
How much sodium carbonate would be required to neutralize it?

4770 grams of sodium carbonate

Explanation:

The reaction that takes place between sodium carbonate and sulfuric acid is:

First we calculate how many H₂SO₄ moles reacted, using the given concentration and volume of solution:

moles = Molarity * Liters

Then we convert H₂SO₄ moles into NaCO₂ moles, using the stoichiometric coefficients:  

Finally we convert 45 NaCO₂ moles into grams, using its molar mass:

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we can conclude that the melting point of table salt is above room temperature (it's actually 801 deg c). the melting point of mercury must be below room temperature (- 39 deg c).