A solution is prepared by dissolving 27.7 g of CaCl2 in 375 g of water. The density of the resulting solution is 1.05 g/mL. The concentration of CaCl2 is % by mass. A solution is prepared by dissolving 27.7 g of CaCl2 in 375 g of water. The density of the resulting solution is 1.05 g/mL. The concentration of CaCl2 is % by mass. 6.24 6.88 7.22 0.0722 0.0688

6.88%

Explanation:

Step 1: Given data

Step 2: Calculate the mass of the solution

The mass of the solution is equal to the sum of the masses of the solute and the solvent.

mSolution = mSolute + mSolvent

mSolution = 27.7 g + 375 g = 402.7 g

Step 3: Calculate the percentage by mass of CaCl₂

We will use the following expression.

%m/m = mass CaCl₂/mass Solution × 100%

%m/m = 27.7 g/402.7 g × 100% = 6.88%

answer; the numbers of valence electrons in the acetic acid molecule (ch3co2h) is 24;