A tower built of Iron is 500 meter tall. What is the change in height (m) if it is exposed to 25 0 Celsius during summer and at 1.00 Celsius during winter. α iron = 1.2 x 10-5/ Celsius

-0.144 m

Explanation:

From the question,

α = Δh/(h₁Δt) Equation 1

Where α = coefficient of linear expansivity of iron, Δh = change in height, h₁ = initial height, Δt = change in temperature.

make Δh the subject of the equation

Δh = α(h₁Δt) Equation 2

Given: α = 1.2×10⁻⁵/°C, h₁ = 500 m,

Δt = (t₂-t₁) Where t₂ and t₁ = Final and initial temperature respectively.

Δt = (1-25) = -24 °C

Substitute these values into equation 2

Δh =  1.2×10⁻⁵[500×(-24)]

Δh = 1.2×10⁻⁵(-12000)

Δh = -0.144 m

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.