When 149 grams of potassium chloride are decomposed, 78 grams of potassium and an amount of chlorine are released. in what mass ratio are potassium and chlorine released?

78 : 71

Explanation:

From the question given above, the following data were obtained:

Mass of KCl = 149 g

Mass of K = 78 g

Mass ratio of K and Cl =?

Next, we shall determine the mass of Cl in the compound. This can be obtained as follow:

Mass of KCl = 149 g

Mass of K = 78 g

Mass of Cl =?

Mass of Cl = (Mass of KCl) – (Mass of K)

Mass of Cl = 149 – 78

Mass of Cl = 71 g

Finally, we shall determine the mass ratio of K and Cl. This can be obtained as follow:

Mass of K = 78 g

Mass of Cl = 71 g

Mass ratio of K and Cl =?

Mass ratio = mass of K / mass of Cl

Mass ratio = 78 / 71

Therefore, potassium, K and chlorine, Cl are released in mass ratio of 78 : 71

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation:

u i forgot the answer?