9.(08.02 HC) How many liters of 4.0 M NaOH solution will react with 1.8 mol H,50,7 (Remember to balance the equation.) H2SO4 + NaOH - Na SO, + H2O (5 points) O 0.90 L 01.02 01.12 02.11​

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2