the process to determine which of the following compounds has the most silver in one mole : AgCl 2 AgNO 3 , Ag 2 O, Agl

The compound silver oxide, Ag₂O has the most silver in one mole of the compound.

Explanation:

From the formula of each of the compounds given:

AgCl₂ : there are one mole of silver atoms for every two moles of chlorine atoms in the compound, silver chloride, AgCl₂

AgNO₃: there are one mole of silver atoms for every one atom of nitrogen and three atoms of oxygen in the compound, silver trioxonitrate (v), AgNo₃.

Ag₂O : there are two atoms of silver for every atom of oxygen in one mole of silver oxide.

AgO : there are one mole of silver atoms for very one mole of iodine atoms in one mole of silver iodide.

Therefore, one mole of silver oxide, Ag₂O has the most silver in one mole of the compound.

the atomic mass is the bottom number on the element.

-steel jelly

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol