Draw the structure of the compound identified by the simulated H1 NMR and C13 NMR spectra. The molecular formula of the compound is C10H12O . (Blue numbers next to the lines in the H1 NMR spectra indicate the integration values.) The proton NMR spectrum has 6 resonances. There is a triplet at 9.8 ppm integrating to 1 proton. There are two sets of doublets, each integrating to two protons, at 7.2 ppm. There is a doublet at 3.8 ppm integrating to 2 protons. There is a quartet at 2.7 ppm integrating to 2 protons. There is a triplet at 1.2 ppm integrating to 3 protons. The carbon 13 NMR has 8 peaks, located at 15, 28, 51, 143 and 199 ppm. There are also 3 peaks between 125 and 130 ppm.

it forms an anion that has a larger radius. anions have a negative charge and are larger than the original atom.

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.