The reversible reaction is given: 2SO2 + O2↔ 2SO3. The velocity constant is equal to 0.2. The initial concentrations of SO2 and O2 are 2.5 and 1.5 mol / liter. 1. Calculate the initial velocity
2. Calculate the speed when 25% of SO2 is wasted.
3. How many times does the reaction speed increase, when we increase the pressure by 3 times.
4. Show how and how much the reaction speed changes when its development temperature drops from 30oC to 0oC. (Coefficient 3)

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

c

explanation: