How many grams of Fe2O3 are formed when 51.3 grams of iron, Fe, react completely with oxygen, O2? 4 Fe + 3 O2 --> 2 Fe2O3

73.4 g of are formed when 51.3 grams of iron react completely with oxygen.

Explanation:

To calculate the moles :

The balanced chemical reaction is:

As is the limiting reagent as it limits the formation of product.

According to stoichiometry :

4 moles of produce = 2 moles of

Thus 0.92 moles of will produce=  of

Mass of

Thus 73.4 g of are formed when 51.3 grams of iron react completely with oxygen.

i belive it is water