How many mL of 0.40 M barium chloride are needed to react 175 mL of 1.50 M ammonium phosphate in the precipitation of barium phosphate?

656.25 mL

Explanation:

M1 = 0.40 M

M2 = 1.50 M

V2 = 175 mL

Plug those values into the equation:

M1V1 = M2V2

(0.40)V1 = (1.50)(175)

---> V1 = 656.25 mL

< > according to newton's third law of motion, forces always act in equal but opposite pairs. another way of saying this is for every action, there is an equal but opposite reaction.< >