What is the final molarity of a solution when 250 mL H2O is added to 150 mL
0,040 M NaOH(aq)?

0.015M is the final molarity of the NaOH solution

Explanation:

A solution of 0.040M NaOH is diluted from 150mL to 250mL + 150mL = 400mL. That means the solution is diluted:

400mL / 150mL = 2.667 times.

As the original solution has a concentration of 0.040M, the diluted solution has a concentration of:

0.040M / 2.667 =

0.015M is the final molarity of the NaOH solution

the catch is that the top numbers are atomic masses the bottom numbers are the numbers of protons and electrons in an uncharged atom. they are the number of that atoms as you would find them on the periodic table. further, the numbers on the left are used to determine the missing numbers on the right

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

The correct answer is "false"