If 74.5 m of oxygen are collected at a pressure of 98.0 kPa, what volume will the gas occupy if the pressure is changed to 90.4 kPa?

80.8 mL

Explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 74.5 mL

Initial pressure (P₁) = 98.0 kPa

Final pressure (P₂) = 90.4 kPa

Final volume (V₂) =?

The final volume of the gas can be by using the Boyle's laws equation as follow:

P₁V₁ = P₂V₂

98 × 74.5 = 90.4 × V₂

7301 = 90.4 × V₂

Divide both side by 90.4

V₂ = 7301 / 90.4

V₂ = 80.8 mL

Thus, the volume of the gas is 80.8 mL