At conditions of 785.0 torr of pressure and 15.0 °C temperature, a gas occupies a volume of 45.5 mL. What will be the volume of the same gas at 745.0 torr and 30.0 °C?

50.4 mL

Explanation:

Step 1: Given data

Step 2: Convert the temperatures to Kelvin

We will use the following expression.

K = °C + 273.15

K = 15.0°C + 273.15 = 288.2 K

K = 30.0°C + 273.15 = 303.2 K

Step 3: Calculate the final volume occupied by the gas

We will use the combined gas law.

P₁ × V₁ / T₁ = P₂ × V₂ / T₂

V₂ = P₁ × V₁ × T₂/ T₁ × P₂

V₂ = 785.0 torr × 45.5 mL × 303.2 K/ 288.2 K × 745.0 torr = 50.4 mL

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)