How many particles are in a 34 g sample of Al2(SO4)3?
please help!

5.98 × 10^22 particles

Explanation:

To get the number of particles (nA) in a substance, we multiply the number of moles of the substance by Avogadro's number (6.02 × 10^23)

The mass of Al2(SO4)3 given in this question is as follows: 34grams.

To convert this mass value to moles, we use;

Mole = mass/molar mass

Molar Mass of Al2(SO4)3 = 27(2) + {(32 + 16(4) }3

= 54 + (32 + 64)3

= 54 + 288

= 342g/mol

mole (n) = 34/342

n = 0.0994mol

number of particles (nA) of Al2(SO4)3 = 0.0994 × 6.02 × 10^23

= 0.598 × 10^23

= 5.98 × 10^22 particles

answer: h+ its less than oh

explanation:

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.