Basic Stoichiometry Part 1: Mole ←→ Mass Conversions
Choose 2: Convert the following number of moles of chemical into its mass in grams.
1. 0.436 moles of (NH4)Cl = g
2. 0.50 moles of Ca(NO3)2 = g
Choose 2: Convert the following masses into their corresponding number of moles.
3. 23.5 g of NaCl = moles
4. 79.9 g of KMnO4 =moles
5) The combustion of a sample of butane, C4H10 (lighter fluid), produced 2.46 grams of water.

1. 23.3 g

2. 82 g

3. 0.402 mol

4. 0.506 mol

Explanation:

We can convert moles (n) to mass (m) using the following expressions that include the molar mass (M).

n = m/M

m = n × M

1. The molar mass of NH₄Cl is 53.49 g/mol.

m = 0.436 mol × 53.49 g/mol = 23.3 g

2. The molar mass of Ca(NO₃)₂ is 164.09 g/mol.

m = 0.50 mol × 164.09 g/mol = 82 g

3. The molar mass of NaCl is 58.44 g/mol.

n = 23.5 g/(58.44 g/mol) = 0.402 mol

4. The molar mass of KMnO₄ is 158.03 g/mol.

n = 79.9 g/(158.03 g/mol) = 0.506 mol

so what is the problem with your lab report and whats the subject of the lab report? i will you

hey there!

mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b