How many grams of KOH are required to make 125mL of a 0.50M solution?

3.51 g

Explanation: M(KOH)= 39.10 + 16 + 1.008 = 56.108 g/mol

Amount of substance is n= m/M = cV and mass m= McV

Volume in litres is 0.125 l

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.