How many Faraday is needed to deposit 0.2 g of Calcium (Ca) from CaCl2 solution using electrolysis process.

0.01 faraday

Explanation:

We'll begin by writing the balanced equation. This is illustrated below:

CaCl₂ (aq) —> Ca²⁺ (aq) + 2Cl¯ (aq)

Ca²⁺ (aq) + 2e —> Ca

Molar mass of Ca = 40 g/mol

Mass of Ca from the balanced equation = 1 × 40 = 40 g

1 mole of electron (e) = 1 faraday

2 moles of electrons (e) = 2 × 1 faraday

2 moles of electrons (e) = 2 faraday

From the balanced equation above,

40 g of Ca was deposited by 2 faraday.

Therefore, 0.2 g of Ca will be deposited by = (0.2 × 2)/40 = 0.01 faraday.

Thus, 0.01 faraday is needed for the reaction.

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer