What is the mass in grams of 9.02x10^28 atoms of Fe​

83.674 grams of Fe

Explanation:

9.02 x 10²⁸ atoms

To convert from atoms to grams, we first need to convert atoms to moles. To do this, divide the atoms by Avogadro's Number, 6.02 x 10²³

9.02 x 10²⁸ ÷ 6.02 x 10²³

= 1.498 moles of Fe

Now we need to convert moles to grams. To do this, multiply the moles by the molar mass of Fe. The molar mass can be found on the periodic table.

1.498 • 55.845

= 83.674 grams of Fe

Hope this helps!

the answer to your question is c