If 143 grams of chromium react with an excess of oxygen, as shown in the balanced chemical equation below, how many grams of chromium oxide can be formed? show all your work for the calculations for full credit.

4cr + 3o2 yields 2cr2o3

209 g

Explanation:

Molecular weight of Cr= 52g/mol

Molecular weight of = 152g/mol

As Oxygen is present in excess, Chromium is the limiting reagent as it limits the formation of product.

of Chromium produces of

Thus 143 g of Chromium(Cr) produces= of Chromium oxide()

the correct answer is option d

explanation:

i was wrong its d because they dont use cm when calculating square roots