The acidic ingredient in vinegar is acetic acid. The pH of vinegar is around 2.4, and the molar concentration of acetic acid in vinegar is around 0.85 M. Based on this information, determine the value of the acid ionization constant, Ka, for acetic acid.

The value of acid ionization constant for acetic acid is

Explanation:

 cM              0             0

So dissociation constant will be:

Give c= 0.85 M and = 2.4

Putting in the values we get:

Thus the value of acid ionization constant for acetic acid is

it is a good conductor

explanation:

the answer is 303.15 or 303