How many grams of H2O is created from 60 grams of O2?
[2 H2 + O2 —> 2 H2O]

Explanation:P = 1 mol x 30.97 g/mol = 30.97 g N = 2 mol x 14.01 g/mol = 28.02 g. O = 4 mol x ... 5.68 g O2 f. Molecules of water produced? 2.46 g H2O ×. 1 mol H2O. 18.02 g H2O. × ... How many grams of sodium sulfate will be produced by the complete ... 2 mol BF3. 3 mol H2. = 1.65 mol BF3 required. Calculate moles H2 required:.

n2(g) + 3h2-> 2nh3(g)   this is the balanced equation

note the mole ratio between n2, h2 and nh3.   it is 1 : 3 : 2   this will be important.

moles n2 present = 28.0 g n2 x 1 mole n2/28 g = 1 mole n2 present

moles h2 present = 25.0 g h2 x 1 mole h2/2 g = 12.5 moles h2 present

based on mole ratio, n2 is limiting in this situation because there is more than enough h2 but not enough n2.

moles nh3 that can be produced = 1 mole n2 x 2 moles nh3/mole n2 = 2 moles nh3 can be produced

grams of nh3 that can be produced = 2 moles nh3 x 17 g/mole = 34 grams of nh3 can be produced

note:   the key to this problem is recognizing that n2 is limiting, and therefore limits how much nh3 can be produced.