How many moles of fluoride gas are needed to react with 42 grams of NaCl? 2NACI(aq) + F2(g) —> 2 NaF(s) + CI2(g)

neutrons are in the middle of the atom and the electrons, which are much smaller.

the temperature of the gas, in k, not celsius.

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally