In order to dilute 1.0l of a 6.00m solution of sodium hydroxide to 0.500m concentration, how much water (in ml) must you add?

To solve this we use the equation, 

M1V1 = M2V2

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

6.00 M ( 1.0 L ) = ( 0.500 M ) V2

V2 = 12 L

Therefore, approximately 11 L of water should be added to the 1 L of 6.00 M solution. Hope this answers the question. Have a nice day.

idk

explanation:

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