Suppose you wanted to produce 1.00 L of 3.50 M solution of H2SO4. How many grams of the solute are needed to make this solution?

343g H2SO4

Explanation

1. H2SO4 is the solute

2. Water is the solvent

3. Molarity = moles of solute / liter of solution = n / V

(Note the case of the letters is important in science. N stands for Normal in chemistry a type of concentration, n stands for the number of moles)

Rearrange the formula to find n

n = M x V

Here are the known values,

M = 3.5M

n = x mol

V = 1.00L

Plug it in and solve for n (the number of moles of H2SO4 in the solution)

n = 3.5M x 1.00 L = 3.50 mol of H2SO4

Molecular mass of H2SO4 is 1g/mole H x 2 + 32.1g/mol S + 16g/mol O x 4 = 98.1g/mol H2SO4

mass = number of mole x relative molecular mass

mass = n x 98.1g/mol

mass = 98.1g/mol H2SO4 x 3.50mol H2SO4

= 343g H2SO4 <-answer

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explanation:

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both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .