N sub 2 +3H sub 2 rightwards arrow 2NH sub If 6 liters of hydrogen gas are used, how many liters of nitrogen gas will be needed for the above reaction at STP

2L of nitrogen gas will be needed

Explanation:

Based on the following reaction:

N₂ + 3H₂ → 2NH₃

1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia.

If 6L of hydrogen (In a gas, the volume is directly proportional to the moles, Avogadro's law) react, the volume of nitrogen gas required will be:

6L H₂ * (1mol N₂ / 3 moles H₂) =

the millers tale is the answer.