Hemos preparado una disolución de cloruro de cobre (II) en agua disolviendo 12 g de cloruro de cobre (II) en 98 g de agua, de forma que una vez completamente disuelta ocupa un volumen de 100 cm^3. Calcula la concentración en % en peso y en g/l. ¿Qué concentración tendrán 10 cm^3 de esa disolución? Si evaporamos todo el agua que hay en los 10 cm^3 de disolución, ¿cuánto cloruro de cobre (II) se recupera? ¿Qué tendríamos que hacer para que la disolución esté más diluida?

specific gravity is the density of a substance divided by the density of water. since (at standard temperature and pressure) water has a density of 1 gram/cm3, and since all of the units cancel, specific gravity is usually very close to the same value as density

so "c" is the answer

plz give brainliest

a graduated cylinder.

explanation:

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

since electrons are negative the answer is neagtaive