It takes 2 g of chlorine to sanitize 1,000,000g of water. How much chlorine will it take to sanitize a 40,000-gallon pool? ( 1 gallon =3.7L; the density of water is 1.0g/ml ) Show your work

0.1g (Gallon) of chlorine

Explanation:

Formula

1 gallon = 3.7L; the density of water is 1.0g/ml

Given

2g (gallon) of chlorine to sanitize = 1,000,000g (gallon) of water

Solve

If 2g (gallon) chlorine = 1,000,000g (gallon)

∴, ? chlorine = 40,000

The First step; set up an equation

1000000/2 = 40000/?

The Next step; divide 1 million to 2

1000000 ÷ 2 = 500000

Then, divide the result by 40000

40000 ÷ 500000 = 0.08

In the nearest unit that is 0.1

Therefore, it will take 0.1g (gallon) of chlorine to sanitize a 40,000-gallon pool.

296

Explanation:

1 gallon = 3.7 L

40,000 gallon

= 40,000 × 3.7

= 148,000 L

1 g = 1 / 1000 L

1,000,000 g

= 1,000,000 / 1000

= 1,000 L

Let x be the amount of chlorine that will it take to sanitize a 40,000-gallon pool.

2 : 1,000 : : x : 148,000

2 / 1,000 = x / 148,000

x × 1,000 = 2 × 148,000

x = ( 2 × 148,000 ) / 1,000

= 2 × 148

x = 296 g

Therefore,

296 g of chlorine will it take to sanitize a 40,000-gallon pool.

( I solved using maths )

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6