*Urgent* A balloon has a volume of 31.8 L at a temperature of 46 degrees C. What is the new temperature
of the balloon in degrees C if the volume is changed to 49.2 liters?
Round answers to 0.1 decimals

The new volume will be  

0.7 L

Explanation:

This is an illustration of Charles' law, some of the time called the temperature-volume law. It expresses that the volume of a gas is straightforwardly corresponding to the Kelvin temperature, while pressing factor and sum are held steady.  The condition is  V  1  T  1  =  V  2  T  2  , where  V  is volume and  T  is temperature in Kelvins.  Known  V  1  =  0.5 L  T  1  =  20  ∘  C  +  273.15  =  293 K  T  2  =  150  ∘  C  +  273.15  =  423 K  Obscure  V  2  Arrangement  Revise the condition to confine  V  2  . Substitute the known qualities into the condition and address.  V  2  =  V  1  T  2  T  1  V  2  =  (  0.5  L  ×  423  K  )  293  K  =  0.7 L  adjusted to one huge figure

"the periodic table is arranged in order of atomic number."

the electrical  conductivity  of asolution  of an electrolyte is measured by determining the resistance of thesolution  between two flat or cylindrical electrodes separated by a fixed distance.