How many moles of calcium nitrate would react with 4.55 moles of chromium (III) sulfate to produce calcium sulfate and chromium(III) nitrate?

13.65 moles

Explanation:

The equation of the reaction is;

3Ca(NO3)2 + Cr2(SO4)3 = 3Ca(SO4) + 2 Cr(NO3)3

4.55 moles of chromium (iii) sulfate reacts with calcium nitrate

The mole ratio of Chromium (iii) sulfate to calcium nitrate is 1: 3

Therefore; the moles of calcium nitrate will be given by

 = (4.55/ 1)×3

= 13.65 moles

Hence; 13.65 moles of calcium nitrate would react with 4.55 moles of Chromium (iii) sulfate.

"hydrogen bonding is the attraction of h atoms in the water molecule (slight + charge) to o atoms in a neighboring water molecule (slight - charge); it is a weak interatomic force. but it is still strong enough to the water molecules "stick" together."