Determine the pressure change when a constant volume of gas at 1.00 atm is heated from 20.0 c to 30.0 c

Hello!

Determine the pressure change when a constant volume of gas at 1.00 atm is heated from 20.0 C to 30.0 C

We have the following information:

P1 (initial pressure) = 1 atm

T1 (initial temperature) = 20 ºC (in Kelvin)

TK = TºC+273.15 → TK = 20+273.15 → T1 (initial temperature) = 293.15 K

P2 (final pressure) = ? (in atm)

T2 (final temperature) = 30 ºC (in Kelvin)

TK = TºC+273.15 → TK = 30+273.15 → T2 (final temperature) = 303.15 K

According to the Law of Charles and Gay-Lussac in the study of gases, we have an isochoric (or isovolumetric) transformation when its volume remains constant or equal, if the temperature increases, the pressure increases and, if the temperature decreases, the pressure also decreases, they are directly proportional.then we will have the following formula:

multiply the means by the extremes

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I Hope this helps, greetings ... Dexteright02! =)

the answer would be b i believe