When the reaction
ch3cl(g) + h2o(g) →ch3oh(g) + hcl(g)
was studied, the tabulated data were obtained. based on thesedata, what are the reaction orders?
initial concentrations, m; initial rates, ms-1
exp ch3cl h2o rate, ms-1
1 0.100 0.100 0.182
2 0.200 0.200 1.45
3 0.200 0.400 5.81
a. ch3cl: firstorder h2o: first order
b. ch3cl: second order h2o: first order
c. ch3cl: firstorder h2o: second order
d. ch3cl: second order h2o: second order
explain your answer.

We can express the rate equation in this form:
-r = k A^n B^m

where -r is the rate
k is the rate constant,
A is the concentration of CH3Cl
n is the order with respect to CH3Cl
B is the concentration of H2O
m is the order with respect to H2O

We can solve this by trial and error or by calculus. The first method is easier. The rate constant does not depend on the concentration of the reactant. Assume values of n and m and solve for k in each experiment. The only option that gives really close values of k in each experiment is:
C. CH3Cl: firstorder H2O: second order

Alpha particles have positive charge, beta particles have negative charge, and answer 4 just doesn’t make sense. thus, you are left with only one possible answer.

Ithinks its false. tell me if im wrong