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Chemistry, 25.09.2019 08:00 cbaublitz

Zn(s)+2hcl(aq)= zncl2(aq)+h2(g)
0.306 moles of hcl are required to consume all of the zn in the reaction mixture..
what is the volume of the solution that will deliver the required amount of the concentration is 2.5 m in hcl? what volume is required to prepare this solution from a concentrated (18m)?

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Zn(s)+2hcl(aq)= zncl2(aq)+h2(g)
0.306 moles of hcl are required to consume all of the zn in th...
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