Propionoic acid, c3h6o2, reacting with methanol, ch4o, will produce c4h8o2 and water. if 70.0 g of propionoic acid and 60.0 g of methanol are reacted together, which one will be the limiting reactant?
c3h6o2 + ch4o → c4h8o2 + h2o

First, find the molar masses of each substance.

C3H6O2 = 74 g/mol

CH4O = 32 g/mol

Then, use the molar mass to find how many moles of each are present:

C3H6O2:  

CH4O:  

There is a higher number of moles of CH4O than C3H6O2, so the C3H6O2 will run out faster.  Therefore, C3H6O2 is the limiting reactant.

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