How does eating contribute to the flow of energy in an ecosystem?

The correct answer is-

Flow of energy in an ecosystem ( a large community of life forms that interact with each other as well as their physical environment in a particular area) takes place through food chain.

A food chain is a linear network of different organisms ( occupying different trophic levels) where organisms at one trophic level consumes organisms at previous trophic level and energy flow takes place in the form of organic matter.

Producers ( such plants) prepare their own food through photosynthesis and occupy the first trophic level.

Producers are eaten by primary consumers ( which are generally herbivores such as rabbits).

Primary consumers are eaten by secondary consumers, which are then eaten by tertiary consumers that are eaten by final consumers and then decomposers ( such as Fungi).

Example- Grass → Grasshopper → Frog→ Snake → Hawk → Fungi

part 1: the half-life of the element is 22 years.

part 2: it will take 132.02 year for the sample to decay from 308.0 g to 4.8125 g.

explanation:

part 1: there are two ways to determine the half life time.

first way: the half life time can be determined directly from its definition as it is the time required for the sample to decay to its half concentration.

from the data the initial concentration was 45.0 g and decayed to its half value (22.5 g) in 22.0 years.

second way: the radio active decay is considered first order reaction so we can use the laws of first order reactions.

k = (1/t) ln (a/a-x), where k is the rate constant of the reaction,

t is the time of the reaction

a is the initial concentration of the reactant

a-x is the remaining concentration at time (t)

a = 45.0 g the initial concentration at t = 0 year.

at t = 22 year, a-x = 22.5 g

then k = (1/22 year) ln (45.0 g/ 22.5 g) = 0.0315 year-1.

the half-life time (t1/2) = ln 2/ k = 0.693/ k =0.693/ 0.0315 = 22 years.

part 2:

using the same law k = (1/t) ln (a/a-x),

using the given data; a = 308.0 g and a-x = 4.8125 g and the calculated k from the part 1 (k = 0.0315 year-1)

t = (1/k) ln (a/a-x) = (1/0.0315) ln (308.0/ 4.8125) = 132.02 years

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