What is the standard enthalpy of formation of liquid n-butanol, ch3ch2ch2ch2oh?
ch3ch2ch2ch2oh(l) + 6o2(g) → 4co2(g) + 5h2o(l); δh° = -2675 kj
substance δh°f (kj/mol)
co2(g) -393.5
h2o(l) -285.8

I'm learning about the periodic tables and what each subject's configuration is. for example, hydrogen is 1s^1, but i don't understand how you get that. can someone me understand how to figure out how to figure this out? sorry if the question makes no sense, but it would really a lot if you could me understand! you so much if you can!