How many g of water are required to be mixed with 11.75 g of hgcl in order to make a 0.01 m solution? (refer to the periodic table for atomic weights.) 40 g 5,000 g 2 x 106 g 2 x 108 g

Molar mass HgCl = 200.59+35.453 = 236.043g/mo;
11.75g = 11.75/236.043 = 0.04977 = 0.05mol

HgCl If you mix this with 1000g
H2O you will have 0.05m solutiuon
You want a 0.01m solution: mix with 0.05/0.01*1000 = 5,000g H2O 

Fine out your self ponk

Naoh + hbr -> nabr (salt) + h2o ca (oh)2 + 2hbr - - - > ca (br)2 + 2h2o