Asample of hexane (c6h14) has a mass of 0.580 g. the sample is burned in a bomb calorimeter that has a mass of 1.900 kg and a specific heat of 3.21 j/gik. what amount of heat is produced during the combustion of hexane if the temperature of the calorimeter increases by 4.542 k?

We first calculate the heat released:
Specific heat = 3.21 kJ/kgK
Heat released = heat absorbed by calorimeter
Heat absorbed = mcΔT
= 1.9 x 3.21 x 4.542
= 27.7 kJ

Now, we calculate the moles of hexane present:
Moles = mass / Mr
moles = 0.58 / (12 x 6 + 14)
= 0.0067

Heat of combustion = 27.7 / 0.0067 kJ/mol

ΔH(combustion) = 4,134.3 kJ / mol

It was ernest rutherford