Your answer should have the same number of significant figures as the starting measurement.
872.4 mm =
a. 87.24
b. 8.724
c. 87.2

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"

it would only be the stuff in module eight so you need to study all the lessons in that you also could check the flvs

hope this : )