4fecr2o7 + 8 k2co3 + o2. = 2 fe2o3 + 8 k2cro4 + 8 co2 based on this formula a) how many grams of o2 are required to produce 44.0grams of co2? and b) how many moles of fe2o3 will be produced from 6.8 moles of k2co3?

is there multiple choice answers?

a corroding iron, if that's one of your choices

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally