How many grams of methane gas (ch4) are in a 15.8-liter sample at 1.2 atmospheres and 27°c? show all work used to solve this problem

              12.31 g

Solution:

                Let us suppose that the gas is acting ideally, then according to Ideal Gas Equation,

                                                      P V = n R T

Also,

                                                      n = Mass / M.mass = m / M

So,

                                                      P V = m/M R T

Solving for m,

                                                      m = P V M / R T

Data Given:

                   P = 1.2 atm

                   V = 15.8 L

                   M = 16 g/mol

                   T = 27 C + 273 = 300 K

                   R = 0.0821 atm.L/mol.K

Putting Values,

                       m = (1.2 atm * 15.8 L * 16 g/mol) / (0.0821 atm.L/mol.K * 300 K)

                       m = 12.31 g

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