An 84.84 g sample of steel is added to a 100-ml graduated cylinder with 45.0 ml of water. if the resulting water level is 55.5 ml, what is the volume of the steel?

10.5 mL

Explanation:

This is related to the Archimedes principle which stated that “A body submerged in a fluid at rest experiences an upward vertical thrust equal to the weight of the volume of fluid dislodged by the body." Or in simpler words, the volume of the fluid displaced is equal to the volume of the body submerged in it. So, the volume displaced is:

Volume displaced = 55.5 mL – 45.0 mL = 10.5 mL

Then, the volume of the steel is 10.5 mL