Amixture in which the suspended particles are too small to be seen with the naked eye is a
a) pure substance
b) colloid
c) heterogeneous mixture
d) salt solution

Option (B) is the correct answer.

Explanation:

A substance which cannot be separated by any physical means or whose molecules are consistently distributed throughout the sample is known as a pure substance.

For example, gold, water, carbon dioxide etc are all pure substances.

Whereas a substance whose particles are microscopically and evenly distributed throughout a solution or mixture is known as a colloid. In a colloid particles are very small that they cannot be seen with a naked eye.

For example, milk is a colloid.

A mixture in which particles are not evenly distributed throughout and are not uniform in composition is known as a heterogeneous mixture.

For example, sand in water is a heterogeneous mixture.

A salt solution is a solution that contains different compounds like sodium, potassium, calcium etc that helps in maintaining pH and osmotic pressure in a body.

Thus, we can conclude that a mixture in which the suspended particles are too small to be seen with the naked eye is a colloid.

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g