What amount of heat is removed to lower the temperature of 80 grams of water from 75º c to 45º c? the specific heat of liquid water is 4.18 j/gº c.
a. -10,000 j
b. 10,000 j
c. -8,000 j
d. 8,000 j

The correct answer option A.

Explanation:

Q= heat removed from the water

m= mass of the water = 80 grams

c = heat capacity of water= 4.18 J/g°C      

Q = -10,032 joules -10,000 Joules

Negative sign indicates that heat was removed from the water.

Heat removed from the water of 80 gram of water is 10,032 Joules.Hence, the correct answer option A.

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