Chemistry, 16.09.2019 05:30 luna163

What are the products of the following combustion reaction?
2c2h2(g) + 5o2(g) →

Answers: 1

Show answers

Answers

A combustion reaction of an will generally produce CO2 and H20 -- carbon dioxide and water and/or an oxide

looking at the combustion material C2H2, you know that the end products will be CO2 and H20, so the question is how much of each will you get

well, look at the total amount of carbon atoms, 2 C2, which means a total of 4 carbon atoms in this reaction, since only CO2 has carbon atoms, that means there must be 4 CO2 as an end product and 4 CO2 will use up 4 of 5 O2 molecule leaving only 1 O2 molecule for the H2 reaction.

now O2 has a total of 2 oxygen molecules whereas H20 has only a single oxygen molecule, hence the end product must have 2 H20

check that the H atoms balance out on both sides

Answer from: sandram74691

4CO2 + 2H2O

Explanation:

A complete combustion reaction produce carbon dioxide, water and energy. That is:

Fuel + O2 → CO2 + H2O + Energy

In the reaction given, it will be:

2C2H2 + 5O2 → X CO2 + Y H2O + Energy

Where X and Y are de moles of CO2 y H2O produced, respectively. What is needed now is to balance the equation and find out the value of X and Y.

You can see that from de left side of the equation you have 4 H (2 C2H2) so Y most be equal to 2 so you have 4 H at de right side of the equation (2 H2O). On the other hand, you have 4 C at the left side of the equation (2 C2H2) and just 1 C at the right side ( CO2), in consequence X most be equal to 4 so you have 4 C at both sides (4 CO2). The final equation would be:

2C2H2 + 5O2 → 4CO2 + 2H2O + Energy

To confirm this, you can notice than you have the same amounts of moles of oxygen at both sides: 10 al the left side (5O2) and 10 at the right side (4CO2 + 2H2O, i.e 8 + 2 = 10)

Answer from: Quest

i believe it is c.) 1575 j.

Answer from: Quest

Radon-222 or rn-222 has a half-life of 3.82 days. to determine the fraction of an original sample of rn-222 that remains unchanged after 7.646 days, we calculate the amount of rn-222 remaining after 7.646 days and divide it with the original amount. using 1 gram as a basis and using half-life calculation methods, we can determine that 0.249 or 0.25 grams of rn-222 will remain, and thus the fraction remaining is 0.25 or 1/4.

Another question on Chemistry

Chemistry, 22.06.2019 09:30

In apex! a liquid heated beyond a certain temperature becomes

Answers: 1

Answer

Chemistry, 22.06.2019 12:30

May someone me with these science questions

Answers: 1

Answer

Chemistry, 22.06.2019 20:30

We are hoping to create 5.72 grams of glucose. the plant was given 4.75 liters of co2 and 2.81 g of h20. which reactant was the limiting reagent? how much excess mass did we have of the other reactant?

Answers: 2

Answer

Chemistry, 22.06.2019 20:30

Which of the following is not true about the atomic model of substances?

Answers: 1

Answer

You know the right answer?

What are the products of the following combustion reaction?
2c2h2(g) + 5o2(g) →...

Questions