Asolution of naoh contains 19.2g of solute in 160 liters of solution. what is the molarity of the solution? and steps on how to do it ?

Given: 19.2g of solute(NaOH) in 160L of solution.
Wanted: Molarity(M) of the solution

M = moles of solute/liters of solution

First, we need to turn the grams into moles of solute. By doing so, you need to find the molar mass of NaOH. Which is 39.997 g/mol.

moles of solute = 19.2g * 1 mol/39.997g

19.2/39.997 = moles of solute = 0.480

Now that we have the moles of solute, we can find out the molarity.

M= 0.480 moles of solute/160L = 0.003M

0.003M

Hope this is helpful!