What is the ph of a solution of 0.600 m k2hpo4, potassium hydrogen phosphate?

9.8

Explanation:

The salt K₂HPO₄ will dissociate to form the ions K⁺ and HPO₄⁻², and because of the stoichiometry of the dissociation (1:2:1) [HPO₄⁻²] = 0.600 M. So, two reactions may happen:

HPO₄⁻² + H₂O ⇄ H₂PO₄⁻ + OH⁻

HPO₄⁻² + H₂O ⇄ PO₄⁻³ + OH⁻

H₃PO₄ is a polyprotic acid and have the values of pKa:

pKa1 = 2.15

pKa2 = 7.21

pKa3 = 12.4

In this case, the second and the third equilibrium are presented, thus, the pH depends only on the pKa values, and it will be:

pH = (1/2)*(pKa2 + pKa3)

pH = (1/2)*(7.21 + 12.4)

pH = 9.8

answer: find it ur self

explanation:

answer: the figure is attached herewith.

step-by-step explanation:   we are given to sketch a unit circle and label the terminal points corresponding to

in the attached figure, we have drawn a unit circle, with centre at o(0,0) and radius 1 unit. we have labelled the points a, b, c, d and e corresponding to the angles below

∠aox = 60°,

∠box = 120°,

∠cox = 180°,

∠dox = 240°,

∠eox = 300°.

and the coordinates are a(0.5,1), b(-0.5,1), c(-1,0), d(-0.5,-1) and e(0.5,-1).

thus, the answer is complete.