How many moles of oxygen gas are required to combust 2.8 mol octane, c8h18, completely to co2 and h2o?

The chemical reaction is as follows:

C8H18 + 25/2O2 = 8CO2 + 9H2O

We are given the amount of octane in moles to be used in the reaction. We use this as the starting point in the calculations.

2.8 mol C8H18 ( 25/2 mol O2 / 1 mol C8H18 ) = 35 mol O2 needed. Hope this answers the question.

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