How to prepare 250.00 ml of approximately 1.0 m hcl solution from the 2.5 m hcl solutio?

Add 150 ml of water to 100 ml of 2.5 M stock solution.

Explanation: According to the neutralization law,

where,

= molarity of stock solution = 2.5 M

= volume of stock solution = ?

= molarity of desired solution = 1.0 M

= volume of desired solution = 250 ml

Now put all the given values in the above law, we get the volume of stock solution.

Therefore, 100 ml of 2.5 M of stock solution is taken and 150 ml of water is added to make the volume to 250 ml.

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